Matematika Sekolah Menengah Pertama Q.--f(a) = 7a⁰ × 87a⁰ + 33⁰ - 66a⁰f(3) = ...---pp buat... :v​

lisahagenesulv – April 19, 2023

Q.
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f(a) = 7a⁰ × 87a⁰ + 33⁰ - 66a⁰
f(3) = ...
---
pp buat... :v​

Penjelasan dengan langkah-langkah:

• f(a) = 7a⁰ × 87a⁰ + 33⁰ - 66a⁰
• f(3) = 7(3⁰) × 87(3⁰) + 33⁰ - 66(3⁰)
• f(3) = 7(1) × 87(3⁰) + 33⁰ - 66(3⁰)
• f(3) = 7(1) × 87(1) + 33⁰ - 66(3⁰)
• f(3) = 7(1) × 87(1) + 1 - 66(3⁰)
• f(3) = 7(1) × 87(1) + 1 - 66(1)
• f(3) = ((7 × 1) × (87 × 1)) + 1 - 66(1)
• f(3) = 7 × 87 + 1 - 66(1)
• f(3) = 609 + 1 - ((66 × 1))
• f(3) = 610 - 66
• f(3) = 544

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#CMIIW

f(a) = 7a⁰ × 87a⁰ + 33⁰ - 66a⁰

f(3) = 7(3)⁰ × 87(3)⁰ + 1 - 66(3)⁰

f(3) = 7(1) × 87(1) + 1 - 66(1)

f(3) = 7 × 87 + 1 - 66

f(3) = 609 + 1 - 66

f(3) = 610 - 66

f(3) = 544

- Vin -

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